How do you differentiate g(a)= sin(arcsin(5a))? Calculus Differentiating Trigonometric Functions Differentiating Inverse Trigonometric Functions 1 Answer Alan P. May 6, 2015 sin(arcsin(theta)) = theta So g(a) = sin(arcsin(5a)) is simply g(a)=5s (dg(a))/(da) = 5 Answer link Related questions What is the derivative of f(x)=sin^-1(x) ? What is the derivative of f(x)=cos^-1(x) ? What is the derivative of f(x)=tan^-1(x) ? What is the derivative of f(x)=sec^-1(x) ? What is the derivative of f(x)=csc^-1(x) ? What is the derivative of f(x)=cot^-1(x) ? What is the derivative of f(x)=(cos^-1(x))/x ? What is the derivative of f(x)=tan^-1(e^x) ? What is the derivative of f(x)=cos^-1(x^3) ? What is the derivative of f(x)=ln(sin^-1(x)) ? See all questions in Differentiating Inverse Trigonometric Functions Impact of this question 1683 views around the world You can reuse this answer Creative Commons License