How do you differentiate #f(x)= x/(x+1) #?

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How do you differentiate #f(x)= x/(x+1) #?

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Answer 1 · 2015-03-23T20:55:45

You can use the Quotient Rule where you have:
#f(x)=g(x)/(h(x))#
#f'(x)=[g'(x)h(x)-g(x)h'(x)]/[h(x)]^2#
in your case you get:
#f'(x)=[1(x+1)-x*1]/(x+1)^2=1/(x+1)^2#

Answer 2 · 2015-03-23T20:58:34

Use the quotient rule:

#(T/B)'=(T'B-TB')/B^2#

In this problem#f(x)=x/(x+1)#

#T=x#, so #T'=1#

#B=x+1#, so #B'=1#

#f'(x)=((1)(x+1)-(x)(1))/(x+1)^2=(x+1-x)/(x+1)^2=1/(x+1)^2#

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How do you differentiate #f(x)= x/(x+1) #?

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