How do you differentiate #f(x)=(x^2-cosx/x)/sinx# using the quotient rule?

Question

How do you differentiate #f(x)=(x^2-cosx/x)/sinx# using the quotient rule?

1 Answer

Impact of this question

1211 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-21T15:19:05

if F(x)= #u/v#
the formula goes as follows:

F'(x)= #{(u)'.(v)-(v)'.(u)}/(v)^2#
so,
(u)'= #2x#
(v)'=#[(-sinx)x-cosx]/x^2#
F'(x)= #{(2x)-[(-sinx)x-cosx]/x^2}(sinx)-(cosx)[x^2-cosx/x]}/sin^2x#
now you can solve it further

Science

Math

Humanities

... and beyond

How do you differentiate #f(x)=(x^2-cosx/x)/sinx# using the quotient rule?

1 Answer

Related questions

Impact of this question