How do you differentiate $f (x) = {(x - 2)}^{3} + x$ $f(x)=(x-2)^3+x$ using the sum rule?

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How do you differentiate $f (x) = {(x - 2)}^{3} + x$ $f(x)=(x-2)^3+x$ using the sum rule?

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Answer 1 · 2015-11-26T02:43:15

$3 {(x - 3)}^{2} + 1$ $3(x-3)^2 +1$

Explanation:

Here f(x) is a sum of two functions. Hence differentiation of f(x) would be equivalent to the sum of differentiation of the two functions. Accordingly,

$f '(x) =d/dx (x-3)^3 + d/dx x$
= $3(x-3)^2 +1$
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How do you differentiate $f (x) = {(x - 2)}^{3} + x$ $f(x)=(x-2)^3+x$ using the sum rule?

1 Answer

Explanation:

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How do you differentiate $f (x) = {(x - 2)}^{3} + x$ $f(x)=(x-2)^3+x$ using the sum rule?