How do you differentiate $f(x)=x^2-x-x(x-1)$ using the sum rule?

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Answer 1 · 2015-12-13T18:59:59

$f'(x)=0 , AAx in RR$

Simplifying function into standard polynomial form by multiplying out the brackets we get

$f(x)=x^2-x-x^2+x$

$therefore f'(x)=2x-1-2x+1$

$=0$

How do you differentiate f(x)=x^2-x-x(x-1)f(x)=x^2-x-x(x-1) using the sum rule?