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How do you differentiate #f(x)=(x+1)/(x-1)# using the quotient rule?

1 Answer

Mar 29, 2017

#f'(x) = - 2/(x - 1)^2#

Explanation:

#f(x) = (x + 1)/(x - 1)#

Let say,
#u = x + 1, u' = 1#, and
#v = x - 1, v' = 1#

#f(x) = u/v#, then
#f'(x) = (u'v - uv')/v^2#

#f'(x) = (1(x - 1) - (x + 1)1)/(x - 1)^2#

#f'(x) = (x - 1 - x - 1)/(x - 1)^2#

#f'(x) = - 2/(x - 1)^2#

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