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How do you differentiate #f(x)= 5/x^3 - 3/ x^(1/3)#?

1 Answer

sankarankalyanam

Apr 21, 2018

#color(blue)(f'(x) = -15/x^4 + 1/x^(4/3)#

Explanation:

#f(x) = 5/x^3 - 3 / x^(1/3)#

#f(x) = 5 * x^-3 - 3 * x^-(1/3)#

#(d/(dx)) x^n = n * x^(n-1)#

#:. f'(x) = 5 * -3 * x^-4 - 3 * -(1/3) * x ^-(4/3)#

#f'(x) = -15 x^-4 + x^-(4/3)#

#=> -15/x^4 + 1/x^(4/3)#

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