How do you differentiate #f(x)=(2x+1)/(2x-1)#? Calculus Basic Differentiation Rules Quotient Rule 1 Answer Andrea S. Apr 30, 2017 #d/dx ((2x+1)/(2x-1)) =-4/(2x-1)^2# Explanation: Using the quotient rule: #d/dx ((2x+1)/(2x-1)) = ( (2x-1) d/dx (2x+1) - (2x+1)d/dx(2x-1))/(2x-1)^2# #d/dx ((2x+1)/(2x-1)) = ( 2(2x-1) - 2(2x+1))/(2x-1)^2# #d/dx ((2x+1)/(2x-1)) = ( 4x-2 - 4x-2)/(2x-1)^2# #d/dx ((2x+1)/(2x-1)) =-4/(2x-1)^2# Answer link Related questions What is the Quotient Rule for derivatives? How do I use the quotient rule to find the derivative? How do you prove the quotient rule? How do you use the quotient rule to differentiate #y=(2x^4-3x)/(4x-1)#? How do you use the quotient rule to differentiate #y=cos(x)/ln(x)#? How do you use the quotient rule to find the derivative of #y=tan(x)# ? How do you use the quotient rule to find the derivative of #y=x/(x^2+1)# ? How do you use the quotient rule to find the derivative of #y=(e^x+1)/(e^x-1)# ? How do you use the quotient rule to find the derivative of #y=(x-sqrt(x))/(x^(1/3))# ? How do you use the quotient rule to find the derivative of #y=x/(3+e^x)# ? See all questions in Quotient Rule Impact of this question 4903 views around the world You can reuse this answer Creative Commons License