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How do you differentiate #f(x)=1/(16x+3)^2# using the quotient rule?

1 Answer

Dec 15, 2015

#frac{d}{dx}(frac{1}{(16x+3)^2}) = frac{-32}{(16x+3)^3}#

Explanation:

#frac{d}{dx}(frac{1}{(16x+3)^2}) = frac{(16x+3)^2*frac{d}{dx}(1)-(1)frac{d]{dx}((16x+3)^2)}{[(16x+3)^2]^2}#

#= frac{(16x+3)^2*(0)-(1)(2(16x+3)(16))}{(16x+3)^4}#

#= frac{-32}{(16x+3)^3}#

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