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How do you differentiate # ( cos (x) ) / ( 2 + sin (x) )#?

1 Answer

Shwetank Mauria

Jan 21, 2017

#intcosx/(2+sinx)dx=ln(2+sinx)+c#

Explanation:

Let #u=2+sinx#, then #du=cosxdx# and

#intcosx/(2+sinx)dx#

= #int(du)/u#

= #lnu+c#

= #ln(2+sinx)+c#

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