How do you differentiate #5cosx-2cosx#?

1 Answer
Jim G.
Aug 31, 2016

#-3sinx#

Explanation:

You may have typed this incorrectly because as it is , the expression can be simplified to one term since they are like terms.

That is #5cosx-2cosx=3cosx#

#color(orange)"Reminder " color(red)(|bar(ul(color(white)(a/a)color(black)(d/dx(cosx)=-sinx)color(white)(a/a)|)))#

#rArrd/dx(3cosx)=-3sinx#

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