How do you differentiate #2cos(x)+cos^2(x)#?

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How do you differentiate #2cos(x)+cos^2(x)#?

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Answer 1 · 2017-04-11T18:24:57

#-2sinx-sin2x#

Explanation:

#d/dx(2cosx+cos^2x)#
#" "#
#=d/dx(2cosx)+d/dx(cos^2x)#
#" "#
#=2(d/dx(cosx))+2cos^(2-1)x(d/dx(cosx))#
#" "#
#=2(-sinx)+2cosx(-sinx)#
#" "#
#=-2sinx-2cosxsinx#
#" "#
#=-2sinx-sin2x#

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How do you differentiate #2cos(x)+cos^2(x)#?

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