How do you differentiate #1/x^-0.4#? Calculus Basic Differentiation Rules Power Rule 1 Answer Jess Jul 10, 2018 #1/x^-0.4# #=x^0.4# [reciprocal] therefore by power rule #dy/dx = 0.4x^(0.4-1)# #dy/dx = 0.4x^-0.6# which can be rewritten as #dy/dx=0.4/x^0.6# or #dy/dx = 2/(5x^(3/5))# Answer link Related questions How do you find the derivative of a polynomial? How do you find the derivative of #y =1/sqrt(x)#? How do you find the derivative of #y =4/sqrt(x)#? How do you find the derivative of #y =sqrt(2x)#? How do you find the derivative of #y =sqrt(3x)#? How do you find the derivative of #y =sqrt(x)#? How do you find the derivative of #y =sqrt(x)# using the definition of derivative? How do you find the derivative of #y =sqrt(3x+1)#? How do you find the derivative of #y =sqrt(9-x)#? How do you find the derivative of #y =sqrt(x-1)#? See all questions in Power Rule Impact of this question 2472 views around the world You can reuse this answer Creative Commons License