How do you determine whether the pair (0, 1) is a solution of y+4x-1=0?

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How do you determine whether the pair (0, 1) is a solution of y+4x-1=0?

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Answer 1 · 2017-08-23T13:29:28

See a solution process below:

Explanation:

Substitute $0$ $color(red)(0)$ for $x$ $color(red)(x)$ in the equation. And, substitute $1$ $color(blue)(1)$ for $y$ $color(blue)(y)$ in the equation.

Then, evaluate the left side of the equation.

If the left and right side of the equation are equal the point in the problem is a solution for the equation.

If the left and right side of the equation are not equal the point in the problem is not a solution for the equation.

$y + 4 x - 1 = 0$ $color(blue)(y) + 4color(red)(x) - 1 = 0$ becomes:

$1 + (4 \cdot 0) - 1 = 0$ $color(blue)(1) + (4 * color(red)(0)) - 1 = 0$

$1 + 0 - 1 = 0$ $color(blue)(1) + 0 - 1 = 0$

$1 - 1 = 0$ $color(blue)(1) - 1 = 0$

$0 = 0$ $0 = 0$

Both sides of the equation are equal therefore $(0, 1)$ $(0, 1)$ is a solution for the equation in the problem.

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How do you determine whether the pair (0, 1) is a solution of y+4x-1=0?

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