How do you determine whether (6,-2) is on the line #y=1/2x-5#?
1 Answer
Mar 10, 2018
Explanation:
#"If the point lies on the line then it will satisfy the "#
#"equation"#
#"substitute x = 6 into the equation and if the result is "#
#"y= - 2 then "(6,-2)" is on the line"#
#x=6toy=(1/2xx6)-5=3-5=-2#
#rArr(6,-2)" is on the line "y=1/2x-5#
