How do you determine the binomial factors of #x^3+x^2-4x-4#?

1 Answer
EZ as pi
Jul 19, 2017

#=(x+1)(x+2)(x-2)#

Explanation:

Group the four terms into two pairs, making sure there is a + sign between them. Then take out a common factor from each.

#(x^3 +x^2) + (-4x-4)#

#=x^2(x+1)-4(x+1)" "larr# note the change in signs!

There is a common bracket in the two terms:

#=(x+1)(x^2-4)" "larr# factor the difference of squares

#=(x+1)(x+2)(x-2)#

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