How do you determine #csctheta# given #sintheta=2/5,0^circ<theta<90^circ#?

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How do you determine #csctheta# given #sintheta=2/5,0^circ<theta<90^circ#?

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Answer 1 · 2016-12-16T09:29:56

#csctheta=5/2#

Explanation:

As #sintheta# is positive and is #2/5#

#csctheta# being inverse of #sintheta# i.e. #csctheta=1/sintheta#

= #1/(2/5)=1xx5/2=5/2#

Note that all the trigonometric ratios in range #0^o < theta < 90^o# are positive, but this does not matter as if #sintheta# is positive, #csctheta=1/sintheta# too will have same sign i.e. it will be positive.

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How do you determine #csctheta# given #sintheta=2/5,0^circ<theta<90^circ#?

1 Answer

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