How do you describe the nature of the roots of the equation 2x^2+3x=-3?

2 Answers
Jul 15, 2017

Roots are two complex numbers, conjugate of each other.

Explanation:

2x^2+3x=-3 can be written as 2x^2+3x+3=0. We may now compare it with general equation ax^2+bx+c=0

then Its discriminant is b^2-4ac and for 2x^2+3x+3=0 discriminant is 3^2-4xx2xx3=9-24=-15

As the discriminant is negative, but coefficients of equation are real

te roots of the equation are two complex numbers, conjugate of each other.

The roots are -b/(2a)+-sqrt(b^2-4ac)/(2a)

= -3/4+-sqrt(-15)/4

i.e. -3/4+isqrt15/4 and -3/4-isqrt15/4

Jul 15, 2017

"roots are not real"

Explanation:

"to determine the nature of the roots of a quadratic"

"use the "color(blue)"discriminant"

•color(white)(x)Delta=b^2-4ac

• " if "Delta>0" the roots are real"

• " if "Delta=0" the roots are real and equal"

• " if "Delta<0" the roots are not real"

"rearrange "2x^2+3x=-3" into standard form"

"that is " ax^2+bx+c=0

"add 3 to both sides"

rArr2x^2+3x+3=0

"with " a=2,b=3" and " c=3

rArrDelta=3^2-(4xx2xx3)=9-24=-15

"since "Delta<0" then roots are not real"