How do you convert # y=x# into polar form?

1 Answer
Cesareo R.
Jun 1, 2016

The polar representation of straight #y = x# is #theta = pi/4 + pi k# with #k = 1,2,3,...#

Explanation:

The pass equations are

#{ (x = r cos(theta)), (y = r sin(theta)) :}#

then

#r cos(theta) = r sin(theta)# or #tan(theta) = 1#

Solving for #theta# we have #theta = pi/4 + pi k# with #k = 1,2,...#

The polar representation of straight #y = x# is #theta = pi/4 + pi k# with #k = 1,2,3,...#

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