How do you convert #-y=3y^2-4x^2 -2x # into a polar equation? Trigonometry The Polar System Converting Between Systems 1 Answer Bdub Apr 17, 2016 #3r^2sin^2theta + r sin theta -4r^2 cos^2 theta -2 r cos theta = 0# Explanation: #3y^2+y-4x^2-2x=0# Use formulas #x=rcos theta, y= r sin theta# #3r^2sin^2theta + r sin theta -4r^2 cos^2 theta -2 r cos theta = 0# Answer link Related questions How do you convert rectangular coordinates to polar coordinates? When is it easier to use the polar form of an equation or a rectangular form of an equation? How do you write #r = 4 \cos \theta # into rectangular form? What is the rectangular form of #r = 3 \csc \theta #? What is the polar form of # x^2 + y^2 = 2x#? How do you convert #r \sin^2 \theta =3 \cos \theta# into rectangular form? How do you convert from 300 degrees to radians? How do you convert the polar equation #10 sin(θ)# to the rectangular form? How do you convert the rectangular equation to polar form x=4? How do you find the cartesian graph of #r cos(θ) = 9#? See all questions in Converting Between Systems Impact of this question 1602 views around the world You can reuse this answer Creative Commons License