How do you convert #Y^2=8x# into polar form?

1 Answer
A. S. Adikesavan
Jun 5, 2016

#r = 8 cot theta csc theta#. To trace the parabola, it is sufficient to vary #theta# from #pi/2# to 0, backwards.#and theta in (-pi/2, 0)#.

Explanation:

Use #(x, y) = (r cos theta, r sin theta)#

Here, #r^2 sin^2 theta =8 r cos theta#.

#r =0 and r = 8 cot theta csc theta#

The second equation inludes r = 0, at #theta =+-pi/2#. .

To trace the parabola in the polar mode, it is sufficient to vary #theta#

from #pi/2# to 0, backwards,.#and theta in (-pi/2, 0)#.

Related questions
See all questions in Converting Equations from Polar to Rectangular
Impact of this question
5743 views around the world
You can reuse this answer
Creative Commons License