How do you convert #y^2= 4(x+1)# into polar form? Precalculus Polar Coordinates Converting Equations from Polar to Rectangular 1 Answer Bdub Sep 11, 2017 see below Explanation: Use the formulas #x=rcos theta, y=r sin theta# #y^2 = 4(x+1)# #r^2sin^2 theta=4(rcos theta+1)# #r^2 sin^2 theta=4rcos theta+4# #:.r^2 sin^2 theta-4rcos theta-4=0# Answer link Related questions What is the polar equation of a horizontal line? What is the polar equation for #x^2+y^2=9#? How do I graph a polar equation? How do I find the polar equation for #y = 5#? What is a polar equation? How do I find the polar equation for #x^2+y^2=7y#? How do I convert the polar equation #r=10# to its Cartesian equivalent? How do I convert the polar equation #r=10 sin theta# to its Cartesian equivalent? How do you convert polar equations to rectangular equations? How do you convert #r=6cosθ# into a cartesian equation? See all questions in Converting Equations from Polar to Rectangular Impact of this question 4021 views around the world You can reuse this answer Creative Commons License