How do you convert # x=y²-6y+11 # into polar form? Precalculus Polar Coordinates Converting Equations from Polar to Rectangular 1 Answer Bdub Sep 12, 2017 see below Explanation: Use the formulas #x=rcos theta, y=rsin theta# to substitute into the equation. That is, #x=y^2 -6y +11# #rcos theta = r^2 sin^2 theta -6rsin theta +11# #0=r^2sin^2 theta-6rsin theta-rcos theta +11# Answer link Related questions What is the polar equation of a horizontal line? What is the polar equation for #x^2+y^2=9#? How do I graph a polar equation? How do I find the polar equation for #y = 5#? What is a polar equation? How do I find the polar equation for #x^2+y^2=7y#? How do I convert the polar equation #r=10# to its Cartesian equivalent? How do I convert the polar equation #r=10 sin theta# to its Cartesian equivalent? How do you convert polar equations to rectangular equations? How do you convert #r=6cosθ# into a cartesian equation? See all questions in Converting Equations from Polar to Rectangular Impact of this question 1933 views around the world You can reuse this answer Creative Commons License