How do you convert #X + Y = 0# into polar form?

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Answer 1 · 2016-06-04T19:42:35

#theta = -pi/4, forall r in R#

The pass equations

#{ (x = r cos(theta)), (y = r sin(theta)) :}#

substituting

#r cos(theta) + r sin(theta) = 0#
#r(cos(theta)+sin(theta))=0#
#forall r ->tan(theta) = -1#

solving

#theta = -pi/4+k pi, k = 0,1,2,3...#

then

#theta = -pi/4, forall r in R#