How do you convert #x^2+y^2=9# into polar form?

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How do you convert #x^2+y^2=9# into polar form?

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Answer 1 · 2015-12-29T11:47:33

Use the substitutions #x = rcos(theta)# and #y = rsin(theta)#

Explanation:

Use the substitutions #x = rcos(theta)# and #y = rsin(theta)#
Then the equation becomes
#r^2cos^2(theta) + r^2sin^2(theta) = 9#
#r^2(cos^2(theta) + sin^2(theta) ) = 9#
Because we know that #cos^2(theta) + sin^2(theta) = 1#
this gives #r^2 = 9# and hence #r= 3#

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How do you convert #x^2+y^2=9# into polar form?

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