How do you convert #x^2 = 6y# into polar form? Precalculus Polar Coordinates Converting Equations from Polar to Rectangular 1 Answer Binayaka C. Apr 15, 2018 Polar form is # r = tan theta*sec theta# Explanation: #x^2=6 y #. The relation between polar and Cartesian coordinates are #r^2=x^2+y^2 , tan theta =y/x , x=r cos theta , y=r sin theta # # x^2=6 y :. (r cos theta)^2= r sin theta # or #r cos^2 theta= sin theta # or #r = sin theta/ cos^2 theta or r = tan theta*sec theta# Polar form is # r = tan theta*sec theta# [Ans] Answer link Related questions What is the polar equation of a horizontal line? What is the polar equation for #x^2+y^2=9#? How do I graph a polar equation? How do I find the polar equation for #y = 5#? What is a polar equation? How do I find the polar equation for #x^2+y^2=7y#? How do I convert the polar equation #r=10# to its Cartesian equivalent? How do I convert the polar equation #r=10 sin theta# to its Cartesian equivalent? How do you convert polar equations to rectangular equations? How do you convert #r=6cosθ# into a cartesian equation? See all questions in Converting Equations from Polar to Rectangular Impact of this question 7632 views around the world You can reuse this answer Creative Commons License