How do you convert #x^2 = 6y# into polar form?

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Answer 1 · 2018-04-15T12:52:13

Polar form is # r = tan theta*sec theta#

#x^2=6 y #. The relation between polar and Cartesian coordinates

are #r^2=x^2+y^2 , tan theta =y/x , x=r cos theta , y=r sin theta #

# x^2=6 y :. (r cos theta)^2= r sin theta # or

#r cos^2 theta= sin theta # or

#r = sin theta/ cos^2 theta or r = tan theta*sec theta#

Polar form is # r = tan theta*sec theta#

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