How do you convert #(theta)=(-7pi)/4# into cartesian form? Precalculus Polar Coordinates Converting Equations from Polar to Rectangular 1 Answer Bdub Sep 11, 2017 see below Explanation: Use the formula #tan theta =y/x# #theta=tan^-1 (y/x)# Therefore, #theta=(-7pi)/4# #tan^-1 (y/x)=(-7pi)/4# #y/x=tan((-7pi)/4)# #y/x = 1# #:.y=x# Answer link Related questions What is the polar equation of a horizontal line? What is the polar equation for #x^2+y^2=9#? How do I graph a polar equation? How do I find the polar equation for #y = 5#? What is a polar equation? How do I find the polar equation for #x^2+y^2=7y#? How do I convert the polar equation #r=10# to its Cartesian equivalent? How do I convert the polar equation #r=10 sin theta# to its Cartesian equivalent? How do you convert polar equations to rectangular equations? How do you convert #r=6cosθ# into a cartesian equation? See all questions in Converting Equations from Polar to Rectangular Impact of this question 2743 views around the world You can reuse this answer Creative Commons License