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How do you convert the rectangular equation #x^2 + y^2 = 6x# to polar form?

1 Answer

Dec 6, 2015

#r=6cos(theta)#

Explanation:

#x^2+y^2 = r^2color(white)("XXXXXXXX")#[1]

#x/r = cos(theta)#

#rarr x=r*cos(theta)#

#rarr 6x = 6r*cos(theta)color(white)("XXXX")#[2]

Combining [1] and [2]
#x^2+y^2=6x#

#rarr r^2 = 6r*cos(theta)#

#rarr r= 6cos(theta)#

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