How do you convert the rectangular equation ##(x - 2)^2 + y^2 = 9# into polar form?

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Answer 1 · 2016-02-02T11:31:55

#r^2 =5+4 r cos theta#

#r^2 cos ^2 theta-4 r cos theta+4+r^2 sin^2 theta=9#

#r^2 cos ^2 theta+r^2 sin^2 theta-4 r cos theta+4=9#

#r^2 (cos ^2 theta+ sin^2 theta)-4 r cos theta+4=9#

but #(cos ^2 theta+ sin^2 theta)=1#

therefore

#r^2 *1-4 r cos theta+4=9#

#r^2 =5+4 r cos theta#

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