How do you convert the polar point #(1,-pi/2)# into rectangular form?
1 Answer
Aug 10, 2016
Explanation:
To convert from
#color(blue)"polar to rectangular form"#
#color(orange)"Reminder"#
#color(red)(|bar(ul(color(white)(a/a)color(black)(x=rcostheta , y=rsintheta)color(white)(a/a)|)))# here r = 1 and
#theta=-pi/2#
#rArrx=1xxcos(-pi/2)=1xx0=0# and
#y=1xxsin(-pi/2)=1xx(-1)=-1#
#rArr(1,-pi/2)to(0,-1)" in rectangular form"#
