How do you convert #(sqrt2, 1)# into polar form?

1 Answer
Binayaka C.
May 27, 2018

Polar coordinates are #(sqrt3, 35.26^0)#

Explanation:

Rectangular coordinates :#(x,y)=( sqrt 2,1)#

#r=sqrt(x^2+y^2) = sqrt (2+1) =sqrt 3 ; tan alpha=|y/x|=1/ sqrt 2#

#:. alpha=tan^-1(1/ sqrt 2) ~~ 35.264^0 #.Since #(sqrt 2,1)# lies

on 1st quadrant # theta=alpha ~~35.264^0#

Hence Polar coordinates are #(sqrt3, 35.26^0)# [Ans]

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