How do you convert #rsin(theta)=ln(r)+ln[cos(theta)]# into cartesian form? Precalculus Polar Coordinates Converting Equations from Polar to Rectangular 1 Answer A. S. Adikesavan Feb 14, 2017 #y=ln x, x >0#. Explanation: The conversion formula is #r(costheta, sintheta)=(x, y)#. Here, #y=lnr=ln(x/r)=ln(r(x/r))=lnx#. Answer link Related questions What is the polar equation of a horizontal line? What is the polar equation for #x^2+y^2=9#? How do I graph a polar equation? How do I find the polar equation for #y = 5#? What is a polar equation? How do I find the polar equation for #x^2+y^2=7y#? How do I convert the polar equation #r=10# to its Cartesian equivalent? How do I convert the polar equation #r=10 sin theta# to its Cartesian equivalent? How do you convert polar equations to rectangular equations? How do you convert #r=6cosθ# into a cartesian equation? See all questions in Converting Equations from Polar to Rectangular Impact of this question 5800 views around the world You can reuse this answer Creative Commons License