How do you convert #r=cotthetacsctheta# into cartesian form?

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Answer 1 · 2016-06-29T17:46:11

#y^2 = x#

you know that

#x = r cos theta#
#y =r sin theta#

and

#cot theta csc theta = cos theta / sin theta * 1 / sin theta#

so

#r = (x/r)/(y/r)*1/(y/r) = (xr)/y^2#

or #y^2 = x#