How do you convert #r=cos(theta)# in rectangular form? Precalculus Algebraic Modeling Analyzing Data 1 Answer KillerBunny Dec 4, 2015 #x^2+y^2=x# Explanation: Multiply both sides by #r#: #r^2=rcos(theta)# Use the formulas #r^2=x^2+y^2# and #x=rcos(theta)#: #x^2+y^2=x# Answer link Related questions What are common mistakes students make when assigning variables in data analysis? How do I assign a variable? If a problem says one number is twice as large as another, which number should I choose as my variable? How do I determine whether a given relation is a function? Is the set #{(1, 4), (2, 5), (3, 5), (4, 6), (5, 7)}# a function? How do you evaluate the limit as x approaches infinity given the function #((3x-2)(2x+1))/x^2#? How to express z= 1/(1-i) in polar form? How do you find the factors of #f(z)# over C if #f(z)=2z^3+3z^2-14z-15#? Question #f8e6c Demonstrate that #2^n+6^n# is divisible by #8# for #n=1,2,3,cdots # ? See all questions in Analyzing Data Impact of this question 34304 views around the world You can reuse this answer Creative Commons License