How do you convert #r = 8 sin θ# into rectangular equations?
1 Answer
Feb 8, 2016
# x^2 + y^2 = 8y #
Explanation:
using : y =
# rsintheta rArr sintheta = y/r # then r
# = (8y)/r # ( multiply both sides by r )
hence :
# r^2 = 8y # (now using
# r^2 = x^2 + y^2 # )
# rArr x^2 + y^2 = 8y #
