How do you convert #r=6/(2-cos(theta))# into cartesian form?
1 Answer
Nov 8, 2016
The cartesian form is
Explanation:
The formulae used are
and
Rewring the polar form as
Replacing
We get
replacing
Squaring both sides
graph{3x^2-12x+4y^2-36=0 [-7.9, 7.9, -3.95, 3.95]}