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How do you convert #r=-4cos(theta)# into cartesian form?

1 Answer

Shwetank Mauria

Jun 5, 2016

#x^2+y^2+4x=0#

Explanation:

To convert polar form of equation to Cartesian form, one can use #rcostheta=x# and #rsintheta=y#. From this we also get #r^2=x^2+y^2#.

Hence, #r=-4costheta# can be written as

#r^2=-4rcostheta# or

#x^2+y^2=-4x# or

#x^2+y^2+4x=0#

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