How do you convert $r = \frac{45}{5 sin (t) + 36 cos (t)}$ $r= 45 / (5sin(t)+36cos(t))$ into cartesian form?

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How do you convert $r = \frac{45}{5 sin (t) + 36 cos (t)}$ $r= 45 / (5sin(t)+36cos(t))$ into cartesian form?

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Answer 1 · 2016-09-01T01:39:07

$5 y + 36 x = 45$ $5y+36x=45$

Explanation:

The relation between Cartesian coordinates $(x, y)$ $(x,y)$ and polar coordinates $(r, t)$ $(r,t)$ is given by $x = r cos (t)$ $x=rcos(t)$ and $y = r sin (t)$ $y=rsin(t)$ .

Hence, $r = \frac{45}{5 sin (t) + 36 cos (t)}$ $r=45/(5sin(t)+36cos(t))$

$\Leftrightarrow 5 r sin (t) + 36 r cos (t) = 45$ $hArr5rsin(t)+36rcos(t)=45$ or

$5 y + 36 x = 45$ $5y+36x=45$

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How do you convert $r = \frac{45}{5 sin (t) + 36 cos (t)}$ $r= 45 / (5sin(t)+36cos(t))$ into cartesian form?

1 Answer

Explanation:

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How do you convert r= 45 / (5sin(t)+36cos(t)) r=455sin(t)+36cos(t)r= 45 / (5sin(t)+36cos(t)) into cartesian form?

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How do you convert $r = \frac{45}{5 sin (t) + 36 cos (t)}$ $r= 45 / (5sin(t)+36cos(t))$ into cartesian form?