How do you convert #r = 3sin2θ# into rectangular form?

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How do you convert #r = 3sin2θ# into rectangular form?

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Answer 1 · 2016-02-19T06:34:15

by putting #sintheta =y/r , cos theta = x/r and r =sqrt(x^2+y^2)#

Explanation:

we get,
given expression is
# r=3*2sintheta*costheta#
or, #r=3*2y/r*x/r#
or,#r^3=6xy#
or,#r^6=36x^2y^2#
or, #(x^2+y^2)^3=36x^2y^2# (putting,#r^2=x^2+y^2#)

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How do you convert #r = 3sin2θ# into rectangular form?

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