How do you convert #r = 3sin(theta)# into a cartesian equation?
1 Answer
Sep 22, 2015
Use
#x^2+y^2 = 3y#
Explanation:
So
#sqrt(x^2+y^2) = (3y)/sqrt(x^2+y^2)#
Multiply both sides by
#x^2+y^2 = 3y#
graph{x^2+y^2-3y=0 [-4.913, 5.087, -0.98, 4.02]}