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How do you convert # r=2sin(theta)# into cartesian form?

1 Answer

A. S. Adikesavan

May 31, 2016

#x^2+y^2-2y=0#

Explanation:

#(x, y)=(r cos theta, r sin theta). r#2=x^2+y^2#.

So, # r^2=2r sin theta#. In cartesian form, this is

#x^2+y^2-2y=0#

This can be stardized to the form

#(x-0)^2+(y-1)^2=1# representing the circle with

center C(0, 1) and radius 1 unit.

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