How do you convert #(r^2)(sin2theta)=2# into cartesian form?

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Answer 1 · 2016-07-01T21:52:17

# y = 1/x#

#(r^2)(sin2theta)=2#

frim trig we know that

#sin 2 theta = 2 sin theta cos theta#

and in polar coords
#= 2* y/r* x/r = 2 (xy)/r^2#

so #(r^2)( 2 (xy)/r^2)=2#

#\implies xy = 1# or # y = 1/x#