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How do you convert #r^2= sec2theta# to polar form?

1 Answer

Shwetank Mauria

Jan 27, 2017

#x^2-y^2=1#

Explanation:

The relation between polar coordinates #(r,theta)# and Cartesian coordinates #(x,y)# is

#x=rcostheta#, #y=rsintheta# i.e. #x^2+y^2=r^2#

Hence #r^2=sec2theta# can be written as

#r^2=1/(cos2theta)=1/(cos^2theta-sin^2theta)#

or #r^2cos^2theta-r^2sin^2theta=1#

or #x^2-y^2=1#
graph{x^2-y^2=1 [-10, 10, -5, 5]}

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