How do you convert #r=2(cos(theta))^2# into cartesian form? Trigonometry The Polar System Converting Between Systems 1 Answer Konstantinos Michailidis Feb 27, 2016 It is #(x^2+y^2)^(3/2)=2x^2# Explanation: Hence #x=r*costheta# and #y=r*sintheta# we have that #x^2+y^2=r^2=>r=sqrt(x^2+y^2)# so #r=2*(costheta)^2=>sqrt(x^2+y^2)=2*(x/r)^2=> r^2*(sqrt(x^2+y^2))=2x^2=> (x^2+y^2)^(3/2)=2x^2# Answer link Related questions How do you convert rectangular coordinates to polar coordinates? When is it easier to use the polar form of an equation or a rectangular form of an equation? How do you write #r = 4 \cos \theta # into rectangular form? What is the rectangular form of #r = 3 \csc \theta #? What is the polar form of # x^2 + y^2 = 2x#? How do you convert #r \sin^2 \theta =3 \cos \theta# into rectangular form? How do you convert from 300 degrees to radians? How do you convert the polar equation #10 sin(θ)# to the rectangular form? How do you convert the rectangular equation to polar form x=4? How do you find the cartesian graph of #r cos(θ) = 9#? See all questions in Converting Between Systems Impact of this question 1513 views around the world You can reuse this answer Creative Commons License