How do you convert # r = 1 - cos theta# into cartesian form?

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Answer 1 · 2016-12-06T08:14:37

The answer is #x+(x^2+y^2)=sqrt(x^2+y^2)#

To convert from polar coordinates #(r,theta) # to cartesian coordinates, we use the following equations

#x=rcostheta#

#y=rsintheta#

#r=sqrt(x^2+y^2)#

#r=1-costheta#

#costheta=1-r#

#x/r=1-r#

#x=r-r^2#

#x=sqrt(x^2+y^2)-(x^2+y^2)#

#x+(x^2+y^2)=sqrt(x^2+y^2)#