How do you convert #e^(3-4i)# into cartesian form? Precalculus Polar Coordinates Converting Equations from Polar to Rectangular 1 Answer A. S. Adikesavan Aug 25, 2016 #e^3(cos 4-i sin 4)=-13.13-i 15.20#., nearly Explanation: #e^(3-4i)# #=e^3 e^((-4)i)# #=e^3(cos(-4)+i sin (-4)# #=e^3(cos 4 - i sin 4)# #20.0855(cos (229.2^o)- i sin (229.3^o))# #=-13.13-i 15.20#., nearly - Answer link Related questions What is the polar equation of a horizontal line? What is the polar equation for #x^2+y^2=9#? How do I graph a polar equation? How do I find the polar equation for #y = 5#? What is a polar equation? How do I find the polar equation for #x^2+y^2=7y#? How do I convert the polar equation #r=10# to its Cartesian equivalent? How do I convert the polar equation #r=10 sin theta# to its Cartesian equivalent? How do you convert polar equations to rectangular equations? How do you convert #r=6cosθ# into a cartesian equation? See all questions in Converting Equations from Polar to Rectangular Impact of this question 5184 views around the world You can reuse this answer Creative Commons License