How do you convert #9x²-4y²=36# into polar form?

1 Answer
Jim G.
Aug 30, 2016

#r^2=36/(9cos^2theta-4sin^2theta)#

Explanation:

To convert from #color(blue)"cartesian to polar form"#

#color(orange)"Reminder"#

#color(red)(|bar(ul(color(white)(a/a)color(black)(x=rcostheta , y=rsintheta)color(white)(a/a)|)))#

#rArr9(color(red)(rcostheta))^2-4(color(red)(rsintheta))^2=36#

#rArr9r^2cos^2theta-4r^2sin^2theta=36#

#rArrr^2(9cos^2theta-4sin^2theta)=36#

#rArrr^2=36/(9cos^2theta-4sin^2theta)#

Related questions
See all questions in Converting Equations from Polar to Rectangular
Impact of this question
4362 views around the world
You can reuse this answer
Creative Commons License