How do you convert # (7, 5/6 π)# into cartesian form? Precalculus Polar Coordinates Converting Equations from Polar to Rectangular 1 Answer Ratnaker Mehta Jun 14, 2016 #:. (x,y) = (-7sqrt3/2,7/2).# Explanation: Let #(r,theta)# be the given polar co-ords. & let #(x,y)# be their Cartesian conversion. Then, we know that #x=rcostheta, y=rsintheta.# Hence, with #r=7, theta=5pi/6,# we get, #x=7cos5pi/6, y=7sin5pi/6.# #:. x=7cos(pi-pi/6), y=7sin(pi-pi/6).# #:. x=7(-cos(pi/6)), y=7sin(pi/6).# #:. x=-7sqrt3/2, y=7/2# #:. (x,y) = (-7sqrt3/2,7/2).# Answer link Related questions What is the polar equation of a horizontal line? What is the polar equation for #x^2+y^2=9#? How do I graph a polar equation? How do I find the polar equation for #y = 5#? What is a polar equation? How do I find the polar equation for #x^2+y^2=7y#? How do I convert the polar equation #r=10# to its Cartesian equivalent? How do I convert the polar equation #r=10 sin theta# to its Cartesian equivalent? How do you convert polar equations to rectangular equations? How do you convert #r=6cosθ# into a cartesian equation? See all questions in Converting Equations from Polar to Rectangular Impact of this question 1554 views around the world You can reuse this answer Creative Commons License