How do you convert #6y= 5x-2 # into a polar equation?

1 Answer
Jim G.
Jul 10, 2016

#r=-2/(6sintheta-5costheta)#

Explanation:

To convert from #color(blue)"Cartesian to Polar form"#

#color(orange)"Reminder"#

#color(red)(|bar(ul(color(white)(a/a)color(black)(x=rcostheta,y=rsintheta)color(white)(a/a)|)))#

Substitute in Cartesian equation

#rArr6y=5x-2rArr6(rsintheta)=5(rcostheta)-2#

#rArr6rsintheta-5rcostheta=-2#

#rArrr(6sintheta-5costheta)=-2#

#rArrr=-2/(6sintheta-5costheta)" in Polar form"#

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