How do you convert #( 6, pi/ 6) # into cartesian form?

1 Answer
Jim G.
Dec 30, 2016

#(3sqrt3,3)#

Explanation:

To convert from #color(blue)"polar to cartesian form"#

#"That is " (r,theta)to(x,y)#

#color(orange)"Reminder"#

#color(red)(bar(ul(|color(white)(2/2)color(black)(x=rcostheta , y=rsintheta)color(white)(2/2)|)))#

#"here " r=6" and " theta=pi/6#

#rArrx=6cos(pi/6)=6xxsqrt3/2=3sqrt3#

#"and " y=6sin(pi/6)=6xx1/2=3#

#rArr(6,pi/6)to(3sqrt3,3)#

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