How do you convert #( 6, pi/ 6) # into cartesian form?
1 Answer
Dec 30, 2016
Explanation:
To convert from
#color(blue)"polar to cartesian form"#
#"That is " (r,theta)to(x,y)#
#color(orange)"Reminder"#
#color(red)(bar(ul(|color(white)(2/2)color(black)(x=rcostheta , y=rsintheta)color(white)(2/2)|)))#
#"here " r=6" and " theta=pi/6#
#rArrx=6cos(pi/6)=6xxsqrt3/2=3sqrt3#
#"and " y=6sin(pi/6)=6xx1/2=3#
#rArr(6,pi/6)to(3sqrt3,3)#